C++ Program to print the sum of n odd numbers using do while

Program

#include <iostream>
using namespace std;
int main()
{
    int i, n;
    int sum = 0;
    cout << "Enter the value of n \n";
    cin >> n;
    i = 1;
    do
    {
        if (i % 2 != 0)
        {
            sum = sum + i;
        }
        i++;
    } while (i <= n);
    cout << "Sum of all odd numbers from 1 to " << n << " is:" << sum;
    return 0;
}

Output

$g++ sum-of-n-odd-numbers-using-do-while.cpp
$ ./a.out
Enter the value of n 
46
Sum of all odd numbers from 1 to 46 is:529